Chalk−1

Math · Calculus II · Worked example

Test an alternating series

Does 1 − 1/2 + 1/3 − 1/4 + ⋯ converge? How close is the sum of its first ten terms?

Check the conditions

The signs alternate, the sizes 1/n decrease, and 1/n approaches 0, so the alternating series test applies: the series converges.

Absolute or conditional

Without the signs it is the harmonic series, which diverges, so the convergence is conditional.

Watch the partial sums

They step above and below the sum in turn: 1, then 1/2, then 5/6, then 7/12.

1−12+13−14=712

Estimate the error

The first ten terms add to 0.6456, and the error is at most the first term left out, 1/11 ≈ 0.091. The sum is in fact ln 2 ≈ 0.6931, which is 0.0475 away.

Result

It converges conditionally; the first ten terms, 0.6456, are within 1/11 of the sum, ln 2 ≈ 0.6931.

Your turn

Does the series of (−1)ⁿ⁺¹/n² converge absolutely?

Show the answer and explanation

Yes.

Without the signs it is the series of 1/n², a p-series with p = 2 > 1, which converges.

Keep exploring

In Sequences & infinite series, the terms (−1)ⁿ⁺¹/n show the partial sums zigzagging: 1, 0.5, 0.833, 0.583, … narrowing toward 0.693.

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