Chalk−1

Math · Calculus · Concept

Accumulation and the Fundamental Theorem

A running integral connects area accumulated so far with the rate being accumulated.

Move only the upper endpoint

Keep a fixed and define F(x) as signed area from a to x. Changing x adds or removes a thin strip. Negative f means accumulation decreases as x increases.

F⁢(x)=∫axf⁡(t)d⁢t

Why the slope equals the height

The difference F(x+h)−F(x) is the integral over the short interval from x to x+h. Dividing by h gives the average height there. At a point where f is continuous, that average tends to f(x). The running area therefore has derivative f.

F′(x)=f⁡(x)

Why endpoint subtraction works

If G′=f on an interval and f is continuous, F and G have the same derivative. Their difference is constant. Since F(a)=0, F(b)=G(b)−G(a), turning a limiting sum into an endpoint calculation.

∫abf⁡(x)d⁢x=G⁢(b)−G⁢(a)

Common mistakes

  • F(x) is accumulated area, while F′(x) is the current height.
  • Continuity conditions matter; a jump in f need not give a derivative of F at that point.

Work through an example

Find F(x)=∫₀ˣ(t−1)dt and explain when it decreases.

Accumulate a changing signed rate →
Sources and scope

Authored study material. Tool results depend on the stated inputs and model assumptions.