Chalk−1

Math · College algebra · Worked example

Write a quadratic from its vertex

A parabola has vertex (−1, 4) and passes through (1, −4). Find its equation in vertex form and in standard form.

Start from vertex form

The vertex (−1, 4) gives h = −1 and k = 4, so f(x) = a(x + 1)² + 4. Only a is unknown.

Use the other point

Substitute (1, −4) and solve for a.

a⁢(1+1)2+4=−44⁢a=−8a=−2

Write both forms

f(x) = −2(x + 1)² + 4. Expanding gives the standard form.

−2⁢(x+1)2+4−2x2−4⁢x+2

Check

In standard form, −b/(2a) = −(−4)/(2(−2)) = −1, matching the vertex, and f(1) = −2 − 4 + 2 = −4.

Result

f(x) = −2(x + 1)² + 4, or −2x² − 4x + 2 in standard form.

Your turn

Find the quadratic function with vertex (2, −3) whose graph passes through (0, 5).

Show the answer and explanation

f(x) = 2(x − 2)² − 3, or 2x² − 8x + 5.

f(x) = a(x − 2)² − 3, and f(0) = 4a − 3 = 5 gives a = 2.

4⁢a−3=54⁢a=8a=2

Keep exploring

Graph plots the parabola through its vertex (−1, 4) and the point (1, −4).

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