Chalk−1

Chemistry · General chemistry I · Worked example

Predict the shape of ammonia with VSEPR

Predict the electron geometry, molecular geometry and polarity of ammonia, NH₃.

Start from the Lewis structure

5 + 3(1) = 8 electrons: three N–H bonds use 6, and the last 2 form a lone pair on nitrogen.

5+3⁢(1)=8

Count the domains

Three bonds and one lone pair make four electron domains around nitrogen.

Find the electron geometry

Four domains point to the corners of a tetrahedron.

Name the molecular geometry

Only three corners hold atoms; the fourth holds the lone pair. The atoms form a trigonal pyramid, with nitrogen at the apex, and the H–N–H angles are a little less than 109.5° because the lone pair pushes the bonds together.

Decide the polarity

The three N–H bond dipoles all tilt toward nitrogen, the more electronegative atom, and the pyramid keeps them from cancelling: ammonia is polar.

Result

Electron geometry tetrahedral; molecular geometry trigonal pyramidal; polar.

Your turn

Predict the electron geometry and molecular geometry of water, H₂O.

Show the answer and explanation

Tetrahedral electron geometry; bent molecular geometry.

Oxygen has two bonds and two lone pairs: four domains in a tetrahedral arrangement. Only two positions hold atoms, so the molecule is bent, with an angle below 109.5°.

6+2⁢(1)=8

Keep exploring

In VSEPR & molecular polarity, add a fourth hydrogen, remove the lone pair and set the charge to +1. The ammonium ion, NH₄⁺, is tetrahedral, with the ideal 109.5° angles.

Return to the concept →
Sources and scope

Authored study material. Tool results depend on the stated inputs and model assumptions.

Make it concrete

Try in the workspace

Open the example inputs, change a value and keep a useful result on your board.

Open it in VSEPR & molecular polarity Open worked example on a board Hybridization and shape in Chemistry Reference

Your existing work stays on this device. Examples open as editable copies.