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Chemistry · General chemistry II · Worked example

Predict the direction of a reaction with Q

At a certain temperature, Kc = 50.0 for H₂(g) + I₂(g) ⇌ 2HI(g). A mixture contains 0.100 M H₂, 0.200 M I₂ and 0.500 M HI. Is it at equilibrium? If not, which way does it shift?

Write Q

Q has the same form as K: the product concentration over the reactant concentrations, each raised to its coefficient.

Q=[HI]2[H2]⁢[I2]

Substitute the current concentrations

Use the concentrations in the mixture now, not equilibrium values.

(0.500)2(0.100)⁢(0.200)=12.5

Compare Q with K

Q = 12.5 is less than K = 50.0, so the mixture holds too little HI. The reaction runs forward, using up H₂ and I₂, until Q rises to K.

Result

It is not at equilibrium. Q = 12.5 < K = 50.0, so the reaction shifts forward and more HI forms.

Your turn

Another mixture holds 0.0100 M H₂, 0.0100 M I₂ and 0.100 M HI. Which way does it shift?

Show the answer and explanation

In reverse: some HI decomposes.

Q = (0.100)²/((0.0100)(0.0100)) = 100, which is greater than K = 50.0, so the reaction runs in reverse until Q falls to K.

(0.100)2(0.0100)⁢(0.0100)=100

Keep exploring

In Equilibrium & ICE tables, switch the same mixture to an ICE table. It settles at 0.602 M HI, 0.0488 M H₂ and 0.149 M I₂, where Q equals 50.0.

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Compare Q and K in Equilibrium & ICE tables Check Q in Math Open worked example on a board Chemistry formulas: equilibrium and acids

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