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Chemistry · General chemistry II · Worked example

Find the pH of a buffer

Find the pH of a buffer that is 0.100 M acetic acid and 0.150 M sodium acetate. For acetic acid, Ka = 1.8 × 10⁻⁵.

Find pKa

pKa = −log Ka.

pKa=−log(1.8×10−5)=4.74

Apply Henderson–Hasselbalch

Acetate is the base and acetic acid the acid.

pH=4.74+log0.1500.100=4.92

Interpret

There is more base than acid, so the pH sits a little above pKa. The shortcut is safe here: the acetate already present keeps the acid’s own ionization tiny.

Result

pH = 4.92.

Your turn

What ratio of acetate to acetic acid gives a buffer with pH 5.00?

Show the answer and explanation

About 1.8 to 1.

log([A⁻]/[HA]) = 5.00 − 4.74 = 0.26, so [A⁻]/[HA] = 10^0.26 = 1.8.

5.00−4.74=0.26

Keep exploring

In Buffers & titration curves, make the two amounts equal. The pH becomes 4.74, the pKa, whatever the common amount.

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