Chalk−1

Math · College algebra · Worked example

Find the maximum of a quadratic function

A ball is thrown upward from 1.5 m above the ground, and its height after t seconds is h(t) = −4.9t² + 19.6t + 1.5 meters. When does it reach its greatest height, and how high is that?

Recognize the shape

The coefficient of t² is −4.9 < 0, so the graph of h opens downward and its vertex is the highest point.

Find the time of the vertex

Use t = −b/(2a) with a = −4.9 and b = 19.6.

−19.62⁢(−4.9)=2

Find the greatest height

Substitute t = 2.

h⁢(t)=−4.9t2+19.6⁢t+1.5h⁢(2)=21.1

Check with symmetry

The parabola is symmetric about t = 2, so the ball is back at its starting height, 1.5 m, at t = 4.

h⁢(t)=−4.9t2+19.6⁢t+1.5h⁢(4)=1.5

State the model

The model ignores air resistance, which is reasonable for a short throw of a small, heavy ball.

Result

The ball is highest at t = 2 s, 21.1 m above the ground.

Your turn

At a price of p dollars, a shop sells 400 − 20p shirts a week. Which price gives the greatest weekly revenue, and how much is it?

Show the answer and explanation

$10, for $2,000 a week.

Revenue is R(p) = p(400 − 20p) = −20p² + 400p. Its vertex is at p = −400/(2(−20)) = 10, and R(10) = 10 × 200 = 2,000.

R⁢(p)=p⁢(400−20⁢p)R⁢(10)=2000

Keep exploring

Graph plots the height with the peak and the two moments at 1.5 m marked.

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