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Biology · Introductory biology · Worked example

Predict restriction fragments and gel bands

A linear 6000 bp molecule has cuts at 1000 and 3500 bp. Find its fragments and predict the visible band positions.

State the molecule and the digest assumptions

The DNA is linear, 6,000 bp long, with two cuts at 1,000 and 3,500 bp, measured from one end. Assume a complete digest, with both sites cut in every molecule. A linear molecule has two ends, and both count as boundaries.

Mark all boundaries in order

Place 0 at the left end, then the two cuts, then 6,000 at the right end. Four boundaries leave three intervals, so expect three fragments.

0, 1000, 3500, 6000bp
Linear DNA: keep both ends when finding fragment lengths
01000350060001000 bp2500 bp2500 bp

Find each interval length

Subtract each boundary from the next one, in base pairs. The second and third intervals happen to have the same length, and both stay in the list.

1000−0=10003500−1000=25006000−3500=2500

Check that no DNA has been lost

Why add them? Cutting removes no DNA, so the fragments must add up to 6,000 bp. A short sum would mean the piece after the last cut was forgotten.

1000+2500+2500=6000

Predict the band pattern

The two 2,500 bp fragments travel the same distance and make one band. The 1,000 bp fragment travels farther. Three fragments give two bands. Keep both 2,500 bp entries when the digest goes to the gel, because the band holds twice the DNA.

Fragments versus observed size positions
Fragment sizesDistinct band positions
1000, 2500, 2500 bp1000 and 2500 bp

Compare the prediction with the tool

Restriction digest & gel draws the predicted gel under the map. Choose a ladder to compare sizes, or choose Open this digest in Read a gel to record the bands you see. A change in one copy does not update the other.

Result

The fragments are 1,000, 2,500 and 2,500 bp, adding to 6,000. They make two bands, at 2,500 bp and at 1,000 bp, with the 1,000 bp band farther from the well.

Your turn

1. One like the example

A linear 8,000 bp molecule is cut at 1,500, 4,000 and 6,500 bp. Find the fragments and the number of bands.

Show the answer and explanation

Four fragments, 1,500, 2,500, 2,500 and 1,500 bp, which make two bands.

The boundaries are 0, 1,500, 4,000, 6,500 and 8,000. Subtracting neighbors gives 1,500, 2,500, 2,500 and 1,500, which add to 8,000. Equal lengths share a band, so there are bands at 2,500 and at 1,500 bp.

4000−1500=25006500−4000=25008000−6500=15001500+2500+2500+1500=8000
4000−1500=25006500−4000=25008000−6500=15001500+2500+2500+1500=8000

2. A variation

The same two cuts, at 1,000 and 3,500 bp, are made in a circular molecule of 6,000 bp. Find the fragments and the number of bands.

Show the answer and explanation

Two fragments, 2,500 and 3,500 bp, which make two bands.

One fragment runs from 1,000 to 3,500, which is 2,500 bp. The other wraps from 3,500 past the end of the numbering to 1,000, which is 6,000−3,500+1,000 =3,500 bp. A circle has no ends, so two cuts make two fragments.

3500−1000=25006000−3500+1000=35002500+3500=6000

3. Somewhere new

The linear 6,000 bp digest is run with too little enzyme, so some molecules are cut at only one site or at none. Which extra bands appear besides 1,000 and 2,500 bp?

Show the answer and explanation

Bands at 3,500 bp, 5,000 bp and 6,000 bp.

A molecule cut only at 1,000 gives 1,000 and 5,000 bp. One cut only at 3,500 gives 3,500 and 2,500 bp. An uncut molecule stays at 6,000 bp. Each extra band is a sum of neighboring fragments, 1,000+2,500=3,500 and 2,500+2,500=5,000.

1000+2500=35002500+2500=5000

Keep exploring

The digest opens in Restriction digest & gel with cuts at 1000 and 3500 bp. Change the topology to circular and watch three fragments become two.

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After reading

Study it, then try it

Practice the key terms as flashcards, then open the example in its tool, change a value and keep a useful result on your board.

Study the 8 key terms Explore the restriction map Open worked example on a board Restriction-enzyme reference

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