A linear 6000 bp molecule has cuts at 1000 and 3500 bp. Find its fragments and predict the visible band positions.
1
State the molecule and the digest assumptions
The DNA is linear, 6,000 bp long, with two cuts at 1,000 and 3,500 bp, measured from one end. Assume a complete digest, with both sites cut in every molecule. A linear molecule has two ends, and both count as boundaries.
2
Mark all boundaries in order
Place 0 at the left end, then the two cuts, then 6,000 at the right end. Four boundaries leave three intervals, so expect three fragments.
0, 1000, 3500, 6000bp
Linear DNA: keep both ends when finding fragment lengths3
Find each interval length
Subtract each boundary from the next one, in base pairs. The second and third intervals happen to have the same length, and both stay in the list.
1000−0=10003500−1000=25006000−3500=2500
4
Check that no DNA has been lost
Why add them? Cutting removes no DNA, so the fragments must add up to 6,000 bp. A short sum would mean the piece after the last cut was forgotten.
1000+2500+2500=6000
5
Predict the band pattern
The two 2,500 bp fragments travel the same distance and make one band. The 1,000 bp fragment travels farther. Three fragments give two bands. Keep both 2,500 bp entries when the digest goes to the gel, because the band holds twice the DNA.
Fragments versus observed size positions
Fragment sizes
Distinct band positions
1000,2500,2500 bp
1000 and 2500 bp
6
Compare the prediction with the tool
Restriction digest & gel draws the predicted gel under the map. Choose a ladder to compare sizes, or choose Open this digest in Read a gel to record the bands you see. A change in one copy does not update the other.
Result
The fragments are 1,000,2,500 and 2,500 bp, adding to 6,000. They make two bands, at 2,500 bp and at 1,000 bp, with the 1,000 bp band farther from the well.
Your turn
1. One like the example
A linear 8,000 bp molecule is cut at 1,500,4,000 and 6,500 bp. Find the fragments and the number of bands.
Show the answer and explanation
Four fragments, 1,500,2,500,2,500 and 1,500 bp, which make two bands.
The boundaries are 0,1,500,4,000,6,500and 8,000. Subtracting neighbors gives 1,500,2,500,2,500 and 1,500, which add to 8,000. Equal lengths share a band, so there are bands at 2,500 and at 1,500 bp.
The same two cuts, at 1,000 and 3,500 bp, are made in a circular molecule of 6,000 bp. Find the fragments and the number of bands.
Show the answer and explanation
Two fragments, 2,500 and 3,500 bp, which make two bands.
One fragment runs from 1,000 to 3,500, which is 2,500 bp. The other wraps from 3,500 past the end of the numbering to 1,000, which is 6,000−3,500+1,000=3,500 bp. A circle has no ends, so two cuts make two fragments.
3500−1000=25006000−3500+1000=35002500+3500=6000
3. Somewhere new
The linear 6,000 bp digest is run with too little enzyme, so some molecules are cut at only one site or at none. Which extra bands appear besides 1,000 and 2,500 bp?
Show the answer and explanation
Bands at 3,500 bp,5,000 bp and 6,000 bp.
A molecule cut only at 1,000 gives 1,000 and 5,000 bp. One cut only at 3,500 gives 3,500 and 2,500 bp. An uncut molecule stays at 6,000 bp. Each extra band is a sum of neighboring fragments, 1,000+2,500=3,500 and 2,500+2,500=5,000.
1000+2500=35002500+2500=5000
Keep exploring
The digest opens in Restriction digest & gel with cuts at 1000 and 3500 bp. Change the topology to circular and watch three fragments become two.